250=25x^2

Solution for 250=25x^2 equation:

250=25x^2

We move all terms to the left:

250-(25x^2)=0

a = -25; b = 0; c = +250;
Δ = b2-4ac
Δ = 02-4·(-25)·250
Δ = 25000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{25000}=\sqrt{2500*10}=\sqrt{2500}*\sqrt{10}=50\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-50\sqrt{10}}{2*-25}=\frac{0-50\sqrt{10}}{-50}
=-\frac{50\sqrt{10}}{-50}
=-\frac{\sqrt{10}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+50\sqrt{10}}{2*-25}=\frac{0+50\sqrt{10}}{-50}
=\frac{50\sqrt{10}}{-50}
=\frac{\sqrt{10}}{-1}
$